The frequency of an allele is defined as the total number of copies of thatallele in the population divided by the total number of copies of all alleles of the gene. We can calculate populationallele frequencies from genotypenumbers.
13.
a. Frequency of A allele= 210+ 90/500 = 300/500 = 0.6
b. Frequency of a allele = 110+90 /500 = 200/500 = 0.4
c. This is in Hardy Weinberg equilibrium
Because p+ q = 1 in Hardy Weinberg equilibrium
Here 0.4+ 0.6= 1
d.Chi-squaretest for H-W equilibrium can be calculated as the sum of squared deviations, each divided by the expected number.
13. The following genotype frequencies are observed in a population of 500 individuals. Genotype AA Number...
13. The following genotype frequencies are observed in a population of 500 individuals. Number of individuals Genotype AA Аа 45 ad 210 245 Total = 500 Answer the following questions about this population (6 points total) 13d. Assume population size remains constant at 500, and that A is dominant to a. How many individuals would you expect to exhibit the dominant phenotype in the next generation if the population undergoes random mating and does not experience mutation, selection, migration, or...
We have a population of 250 individuals, with the following genotype frequencies: AA = 0.30; Aa = 0.60; aa = 0.10. Calculate the frequency of the A and a allele in this population. Show your work.
Consider a locus of interest that has two alleles: A and a. A diploid individual carrying these alleles can have one of three genotypes: AA, Aa, or aa; a population will consist of some combination of AA, Aa, and aa individuals. The relatively frequency of each of these genotypes makes up the population's structure. Hardy and Weinberg independently figured out that, in the absence of forces that cause evolutionary change, the population structure will 'settle' or default to equilibrium values,...
Assume Hardy-Weinberg equilibrium. In a population with 1000 individuals, if genotype frequencies are equal to AA 50%, Aa 42%, and aa 8%, what is the probability of obtaining a "AA" Zygote? 7% 50% 71% 5%
A population of 100 crayfishes were observed in the wild. Three colors exist in this population; 47 red (RR), 13 orange (RY), and 40 yellow (YY). A. Calculate the observed total number of each allele in the population (1 point) and the observed allele frequencies (1 points). B. Using the Hardy-Weinberg equilibrium equation (p2 +2pq+q2=1.0) calculate what the predicted genotype frequencies would be if under Hardy-Weinberg equilibrium (2 points) and calculate the predicted number individuals of each genotype (2 points)....
1.)If the population frequencies of two alleles at a locus are B = 0.5 and b = 0.5, what is onepossible set of frequencies for the three resulting genotypes that would NOT reflect Hardy- Weinberg equilibrium? 2.)In a population that is in Hardy-Weinberg equilibrium, the frequency of the homozygous recessive genotype is 0.09. What is the frequency of individuals that are homozygous for the dominant allele? 3.)In humans, Rh-positive individuals have the Rh antigen on their red blood cells, while...
1. A population of 2000 peppered moths has the following genotypic frequencies:aa: 0.16, Aa: 0.04. AA: 0.80. a. The frequency of the 'a' allele in this population is (show your work for full credit): frequency of the a allele is __ . Calculate the expected genotypic frequencies under Hardy-Weinberg equilibrium. Is this population in equilibrium for genotypic frequencies? Show all your work for full credit. (Do a rough comparison by eye of the observed and expected frequencies to test for...
Question 2: A blood sample was drawn from individuals in Finland and the following genotype frequencies were observed among the people sampled: FF-99, Ff-418 and ff-483. The critical value to reject is 3.814. (a) Is this population in Hardy-Weinberg equilibrium? (b) Which statistical test did you perform? SHOW ALL WORK- formulae and calculations.
1. A particular gene in a given population of individuals has two alleles, A and a. The frequency of the A allele equals the frequency of the a allele. What are the expected genotype frequencies, assuming the population is in Hardy-Weinberg equilibrium? AA = 0.5, aa = 0.5 AA = 0.25, Aa = 0.50, aa = 0.25 O A = 0.5, a = 0.5 The answer cannot be determined because the allele frequencies are not provided.
The following genotypes were observed in a population: Genotype: JJ (40), Jj (45), jj (50) a. Calculate the observed genotypic and allelic frequencies for this population. b. Calculate the expected numbers of individuals for each genotype if this population were in Hardy- Weinberg equilibrium. c. Using a chi-square test, determine whether the population is in Hardy-Weinberg equilibrium.