Assume Hardy-Weinberg equilibrium. In a population with 1000 individuals, if genotype frequencies are equal to AA...
Assume Hardy-Weinberg equilibrium. In a population with 1000 individuals, if genotype frequencies are equal to AA 50%, Aa 42%, and aa 8%, what is the probability of obtaining a "AA" Zygote?
7%
50%
71%
5%
Homework Answers
50%
AA = 50% = 0.5
A = √0.5
AA zygote = √0.5 × √0.5 = 0.5
Percentage of AA = 0.5 × 100 = 50%
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