Is the population in Hardy Weinberg Equilibrium? Show your work.
Generation 1: p=0.6, q=0.4; population mean fitness =0.9
Generation 2: p'=0.54, q'=0.46
The genotype frequency in the first generation is:
AA: 0.3
Aa: 0.5
aa: 0.2
Is the population in Hardy Weinberg Equilibrium? Show your work.
Homework Answers
Given
Allele frequency of A = 0.6
Allele frequency of a = 0.4
Genotype frequency
AA = 0.3
Aa = 0.5
aa = 0.2
Accordint to hardy weinberg population
Genotye frequency of AA = p2 = 0.6*0.6 = 0.36
Genotye frequency of aa = q2 = 0.4*0.4 = 0.16
Genotye frequency of Aa = 2pq = 2*0.6*0.4= 0.48
This is almost similar to given genotype frequency.
So the population is in hardy Weinberg equilibrium.
Calculate the average excess of fitness for each allele. Show your work.
Given the following allele frequency data, answer the following questions. Generation 1: p=0.6, q=0.4; population mean fitness =0.9 Generation 2: p'=0.54, q'=0.46 Calculate the average excess of fitness for each allele. Show your work.
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