Question

4. A population has two alleles at the height locus. The Tallele is form the tail ons short trait. T is dominant to t. The frequency of the tall phenotype is found to frequency of the short phenotype is found to be 0.64 (64%). Assuming the pop Weinberg Equilibrium, what are the values for p (frequency of the T alle t allele)? Give an actual number. Space for calculations ne i allele is form the tall trait, and the t is for the cy of the tall phenotype is found to be 0.36 (or 36%) and the be 0.04 (64%). Assuming the population is in Hardy- the values for p (frequency of the T allele) and q (frequency of the р - 3. A population has two alleles at the color locus. The R1 allele is for the red trait and the R2 allele 15 OF the white trait. The locus shows incomplete dominance, and the heterozygote is pink. This population is not in Hardy-Weinberg Equilibrium. The frequencies of the phenotypes are: red -0.2 (20%); pink - 0.6 (60%); white-0.2 (20%). What are the allele frequencies? Give an actual number. Space for calculations

Answer 1

Answer 4 :

The frequencies of allele T and t are p and q respectively. TT and Tt are tall whereas tt are short.

Given that 64% express short phenotype, which is a recessive trait. Thus,

q² = 64%

q² = 0.64

q = √0.64

q=0.8

Since the population is in Hardy Weinberg equilibrium, thus p+q=1, which implies p=1-q

=1-0.8

=0.2

Thus,

p = 0.2

q = 0.8

Answer 5:

Let the frequencies of allele R1 and R2 be p and q respectively.

Given,

Red = 0.2 (p² )

Pink = 0.6 (pq)

White = 0.2 (q²)

We can calculate the frequency of allele R1 by using the formula :

f(R1) = p² + 1/2(pq)

= (0.2) + 1/2 (0.6)

= 0.2+0.3

=0.5

Frequency of q= 1-0.5, which is 0.5.

Hence,

p=0.5

q=0.5