Question

Gaseous methane (CH) will react with gaseous oxygen (O) to produce gaseous carbon dioxide (CO) and gaseous water (1,0). Suppose 12.5 g of methane is mixed with 36. g of oxygen. Calculate the minimum mass of methane that could be left over by the chemical reaction. Round your answer to 2 significant digits.

Answer 1

HERE balanced chemical equation

CH4+ 2O2 = CO2 + 2H2O

Molar mass of CH4 and O2 is 16g per mole

That means 16 g CH4 will react with 32 g of O2

1 g CH4 will react with 2 g of O2

So 12.5 g of CH4 will react with 25 g of O2

So here O2 is present 36 g so 11 g O2 is left and

All CH4 finished so CH4 is a limiting reagent

Amount of CH4 left after reaction is 0 gram

Amount of O2 left after reaction is 11 gram