Question

Gaseous methane (CH) will react with gaseous oxygen (02) to produce gaseous carbon dioxide (CO) and gaseous water (H,0). Suppose 1.44 g of methane is mixed with 2.3 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to 2 significant digits. XS ?

Answer 1

The balanced chemical reaction is CHy + 20, 60, 72 H2O now, no. of males of cry - Ginen mass - Molar Mass = 1.449 To gimole 50:09 No. of moles of O2 = 213 g . 32 glmale -0.071 From balanced equation, 1 imale of Chly require amole of O2 : 0.09 mole of My require amole of = 0.09 x 2 = 0.18 mole of O₂

I So, here limiting reagent is O₂ (as it have less no. of moles) Vsing stehiometry CO2 No. of males of O. _ No. of moles of the (where 2 is the stochiamite coefficient) :Noof males of (0+ 0.071 = 0.03 55 A10 (w, we Eroup, So • o na = 9*еи каи Molar May 2. Mass of co₂ = 0.03558 4 4 glmale = 1.5629 . Manimum mas of co produced us -1.691