Balanced chemical reaction is
2CH3CH3 + 7O2 4CO2 + 6H2O
Calculate limiting reactant
mass of ethane = 15 gm
mass of oxygen = 76.5 gm
molar mass of ethane = 30.07 g/mol
molar mass of O2 = 31.9988 g/mol
no. of mole = gm of compound / molar mass
mole of ethane = 15 / 30.07 = 0.49884 mole
mole of O2 = 76.5 / 31.9988 = 2.39 moles
According to balanced chemical eqation 2 mole ethane react with 7 mole O2 molar ratio between ethane to O2 is 2: 7 therefore to react with 2.39 mole of O2 required ethane = 2.39 X 2 / 7 = 0.6829 mole but ethane given only 0.49884 mole therefore ethane is limiting reactant.
According to balanced reaction 2 mole ethane produce 4 mole CO2 molar ratio between ethane to CO2 is 2:4 therefore 0.49884 mole of ethane produce CO2 = 0.49884 X 4 / 2 = 0.99768 mole of CO2
gm of compound = no. of mole X molar mass
moles of CO2 = 0.99768 moles
molar mass of CO2 = 44.01 g/mol
gm of aspirin = 0.99768 X 44.01 = 43.91 gm
Maximum mass of carbon dioxide that could be produced = 43.91A gm
Gaseous ethane (CH,CH,) will react with gaseous oxygen (0) to produce gaseous carbon dioxide (CO) and...
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