Question

Gaseous ethane (CH,CH,) will react with gaseous oxygen (0,) to produce gaseous carbon dioxide (CO.) and gaseous water (H,O), Suppose 6.31 g of ethane is mbxed with 44. g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits. ? Check e Explanation 2019 McGrawH Educaton A Rgs MacBor

Answer 1

dus) given. a) mass of ethane = 6.319. o. moles of ethane = mass - 6.319 molar mass 30g/mol = 0.21 mal b) mass of O2 = ung moles of O₂ = 4ug & 10375 mol. 32g/mol = Solution combutien Ron of Ethane. Ch Chz +702 2002 +3620 Step Hnd limiting Reagent. male pere (officient of CH, CH = moles efficient = 0.21 0.21 ③ moles her Cofficient of O2 = 1.375 72595 - = 0.393 . moles here Coff. Of 027 mole her Coff. of Chcu. 8o. Ethane acts as limiting reaget.

2 CO2 + 3 H₂0 find mass of mentan CH₂ CH₂ + 7 O applied POAC Rule. moles of H0 & Cofficient of it moles of Ch₃CH₂ coffe. of it 0.21 moles of the = males of H2O = 3400 21 = 0.63 mol assume yeild of Bo is 100%, so maximum mass of water = Motes y molou may M = 0.63 mol x 18 g/mon M = 11.34g of tho cha Thank you, May it help you.