Question

Gaseous ethane (CH,CH) will react with gaseous oxygen (02) to produce gaseous carbon dioxide (CO) and gaseous water (H,O). Suppose 2.41 g of ethane is mixed with 18. g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 3 significant digits.

Answer 1

Answer:

Maximum mass of Water that could be produced = 4.34 g

Explanation:

Balanced equation for this reaction:

Balanced equation for this reaction is, 2CH₃ CH₂ + 70 - 4CO₂ + 6H₂O We can also corite this equation as, (divide everything by 2) CH₃ CH₃ + 7 / 202 2 CO₂ + 3 H2O 1 mol mol 2 mol 3 mal

As we can see from the balanced equation 1 mol of ethane reacts with 7/2 mol of oxygen to give 2 mol of carbon dioxide and 3 nol of water.

Now, from the given data in the question let's calculate the moles of ethane and oxygen.

Formula for calculate moles is,

Number of moles = Mass(in g) ÷ Molecular weight(in g/mol)

Moles of Ethane:

Mass of Ethane = 2.41 g

Molecular weight of Ethane = 30 g/mol

No. Of moles of Ethane = 2.41 g ÷ 30 g/mol

No. Of moles of Ethane = 0.0803 mol

Moles of Oxygen:

Mass of Oxygen = 18 g

Molecular weight of Oxygen (O_{​​​​​​2}) = 32 g/mol

No. Of moles of Oxygen = 18 g ÷ 32 g/mol

No. Of moles of Oxygen = 0.5625 mol

Now, according to the balanced equation,

1 mol of Ethane reacts with 7/2 mol of Oxygen to give 3 mol of water.

So,

"0.0803 mol of Ethane" will react with,

"{0.0803×(7/2)} = 0.2811 mol of Oxygen" to give,

"0.0803×3 = 0.2409 mol of Water"

*Note that 0.0803 mol of ethane reacts with 0.2811 mol of Oxygen only. The rest of the moles of Oxygen i.e (0.5625-0.2811)=0.2814 mol of Oxygen remains unreacted.

So, now we found out that "2.41 g of Ethane = 0.0803 mol of Ethane" gives 0.2409 mol of Water.

So, now we need to convert moles of water into grams of water to get our answer.

We will use the following formula,

Mass(in g) = Moles × Molecular weight(in g/mol)

Moles of Water = 0.2409 mol

Molecular weight of Water = 18 g/mol

Put these values in the above formula for mass,

Mass of Water = 0.2409 mol × 18 g/mol

Mass of water = 4.3362 g

Rounding the answer to 3 significant digits give,

Mass of water = 4.34 g