A student took 5 g of H2 and 5 g of N2 for the following reaction.
How many grams of NH3 is expected to form?
3 H2 + N2 --> 2 NH3
According to the balanced reaction,
3 mole H2 require 1 mole N2
3×2 = 6g H2 require 28 g N2
5 g H2 require 28×5/6 g N2
= 23.33 g N2
Since we have only 5 g N2 hence N2 is limiting reagent.
1 mole N2 give 2 mole NH3
28 g N2 give 2×17 = 34 g NH3
5 g N2 give 34×5/28 g NH3
= 6.07 g NH3
A student took 5 g of H2 and 5 g of N2 for the following reaction....
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