I need to return a dynamic array from a class member function and print out the results in main. using pointers and dynamic allocation is required.
class example{
int *test
public:
example(int a){
test = new int[a];
for(int i=0;i<a;i++)
test[i]=i;
}
int *send(){ return test;}
}
int main(){
example a(3);
int *practice = a.send();
int psize = sizeof(a)/sizeof(a[0]);
for(int i=0;i<psize;i++)
cout <<practice[i] << endl;
return 0;
}
Here I implemented dynamic memory allocation function. In my program, I add new function len for returning the size of an array. So now there no need for psize in main.
#include<bits/stdc++.h>
using namespace std;
class example
{
int *test,l; //l is for length of an array
public:
example(int a)
{
l=a;
test = new int[a]; //dynamic memory allocation
for(int i=0;i<a;i++)
test[i]=i;
}
int* send() //return first pointer of an array
{
return test;
}
int len() //return length of an array
{
return l;
}
};
int main()
{
example a(3); //object of example class
int *practice = a.send();
for(int i=0;i<a.len();i++)
{
cout <<*practice<< endl;
practice++; //increment pointer
}
return 0;
}
Output:
0
1
2
I need to return a dynamic array from a class member function and print out the...
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