Now that you have determined the likely value for the exponent associated with the [MO], you...

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Now that you have determined the likely value for the exponent associated with the [MO], you...

Now that you have determined the likely value for the exponent associated with the [MO], you need to determine the exponents related to the [Sn2+] and [H3O+]. Before you do, you must calculate the [MO], [Sn2+] and [H3O+] in your kinetics runs.

In run 1, you mix 7.9 mL of the 43 g/L MO solution (MO molar mass is 327.33 g/mol), 2.50 mL of the 0.040 M SnCl2 in 2.0 M HCl solution, 5.52 mL of 2.0 M HCl solution, and 3.60 mL of 2.0M NaCl solution.

a) What is the [H3O+]? Remember that there is a contribution of H3O+from two solutions.

b)What is the [Sn2+]?

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Answer 1

Answer #1

Total volume of the solution is 19.52ml .

The concentration of H₃O⁺ is mainly from the HCl ( HCl is a strong acid).

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Answer 2

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