Question

Now that you have determined the likely value for the exponent associated with the [MO], you need to determine the exponents related to the [Sn²⁺] and [H₃O⁺]. Before you do, you must calculate the [MO], [Sn²⁺] and [H₃O⁺] in your kinetics runs. (The likely value for the exponent is 1)

In run 1, you mix 7.9 mL of the 43 g/L MO solution (MO molar mass is 327.33 g/mol), 3.13 mL of the 0.040 M SnCl₂ in 2 M HCl solution, 5.49 mL of 2.0M HCl solution, and 3.43 mL of 2.0M NaCl solution. What is the concentration of MO in units of molarity?

In run 1, you mix 7.9 mL of the 43 g/L MO solution (MO molar mass is 327.33 g/mol), 3.13 mL of the 0.040 M SnCl₂ in 2.0 M HCl solution, 5.49 mL of 2.0 M HCl solution, and 3.43 mL of 2.0M NaCl solution. What is the [H₃O⁺]? Remember that there is a contribution of H₃O⁺ from two solutions.

In run 1, you mix 7.9 mL of the 43 g/L MO solution (MO molar mass is 327.33 g/mol), 3.13 mL of the 0.040 M SnCl₂ in 2 M HCl solution, 5.49 mL of 2.0M HCl solution, and 3.43 mL of 2.0M NaCl solution. What is the [Sn²⁺]?

In the previous part, you calculated the concentrations of the components of the reaction mixture for Run 1. Pretend that you also calculated the concentrations for Run 2 and Run 3 and you plot log([Sn²⁺]) vs log(k_expt). The slope of the best fit line is 1. What is the likely exponent for [Sn²⁺]?

Answer 1