Which of the following is the Ksp expression for the ionization of Cu(OH)2 in aqueous solution?
Group of answer choices
a. [Cu2+][OH-]2
b. [Cu+]2[OH2-]
c. [Cu2+][2OH-]
d. [Cu2+][OH2-]/[Cu(OH)2]
Which of the following is the Ksp expression for the ionization of Cu(OH)2 in aqueous solution?...
When aqueous solutions of NH4OH(aq) and CuCl2(aq) are mixed, the products are NH4Cl (aq) and Cu(OH)2(s). What is the net ionic equation for this reaction? Select the correct answer below: Question 12 options: 2 NH4OH(aq)+CuCl2(aq)⟶Cu(OH)2(s)+2NH4Cl(aq) 2NH+4(aq)+2OH−(aq)+Cu2+(aq)+2Cl−(aq)⟶Cu(OH)2(s)+2NH+4(aq)+2Cl−(aq) Cu2+(aq)+2OH−(aq)⟶Cu(OH)2(s) NH+4(aq)+Cl−(aq)⟶NH4Cl(s)
When aqueous solutions of NH4OH(aq) and CuCl2(aq) are mixed, the products are NH4Cl(aq) and Cu(OH)2(s). What is the net ionic equation for this reaction? Select the correct answer below: 2NH4OH(aq)+CuCl2(aq)⟶Cu(OH)2(s)+2NH4Cl(aq) 2NH+4(aq)+2OH−(aq)+Cu2+(aq)+2Cl−(aq)⟶Cu(OH)2(s)+2NH+4(aq)+2Cl−(aq) Cu2+(aq)+2OH−(aq)⟶Cu(OH)2(s) NH+4(aq)+Cl−(aq)⟶NH4Cl(s)
In step1, aqueous ammonia is added to a solution of the three ions. The equilibrium for the ammonia is EQ1: NH3(aq + H2O(l) ßà NH4+(aq) Kb=1.8x10-5 The bismuth(III) ion is precipitated out of the solution as Bi(OH)3. The equilibrium involved is related to the one provided below: EQ2: Bi(OH)3(s) ßà Bi3+(aq) +3OH(aq)- Ksp =3.2x10-40 Manipulate EQ 1 and 2 to solve for the net equation, EQ3: EQ3 (net): 3H2O+ Bi3+(aq) +3NH3(aq) ßàBi(OH)-(s) +3NH4+(aq) Write the mass law expression for the...
Temp 25°C I need to calculate Ksp Cell Voltage for: Cu lo.IM OH Cu(OH)2 KCI 10.1M Cu Cu0.25 Cell Voltage for: Cu lo.IM OH I Cu(OH)2 KCI l0.1M Cu I Cu Cell Voltage for: Cu 1.0 MOH I Cu(OH)2l KCI 0.IM CuICu 0 570 0.20 V Calculate 0.3ス v 0.219V E for: Cu l0.1MOH Cu(OH2l KCI l0.1M Cu Cu E for: Cu l0.1M OH I Cu(OH)2l KCI 0.1M Cu2 Cu Е" for: Cu 11.0 MOH' | Cu(OH)! KCI 10.1 M...
The Ksp for Cu(OH)2 is 4.8x10^-20. Determine the molar solubility of Cu(OH)2 in a buffer solution with pH of 10.1
An acidic solution is 0.01 M in Mg2+, Cu2+, and Fe2+. The pH of the solution is adjusted by adding NaOH. What is the maximum pH that removes only the Cu2+? Mg(OH)2(s) ↔ Mg2+(aq) + 2OH–(aq) Ksp = 6.3 x 10–10 Fe(OH)2(s) ↔ Fe2+(aq) + 2OH–(aq) Ksp = 4.1 x 10–15 Cu(OH)2(s) ↔ Cu2+(aq) + 2OH–(aq) Ksp = 2.2 x 10–20
40. Concentrated aqueous ammonia is added to a solution of copper(II) sulfate. A white precipitate forms. The precipitate dissolves as more ammonia is added, generating an intensely blue solution. Which combination of net ionic equations, in the appropriate order, describes this chemistry?! I Cu?* (aq) + 2OH(aq) Cu(OH)2 (19) II Cu?" (aq) + 2OH(aq) = Cu(OH)2 (8) III Cu(OH)(aq) + 4 NH, (aq) Cu(NH3),?* () + 2OH(aq) IV Cu(OH)2 (8) + 4NH, (aq) Cu(NH3)*(14) + 2OH(aq) V NH3(aq) + H20...
Consider the ionic compound Mn(OH)2(s). Which aqueous solution will decrease the solubility of Mn(OH)2? Ksp Mn(OH)2 = 2 x 10-13 A. NaCl(aq) B. CaCl2(aq) C.HCl(aq) D. KOH(aq) E. H2SO4(aq)
a. Using the Ksp value for Cu(OH)2 (1.6 x 10-19) and the overall formation constant for Cu(NH3)42+ (1.0 x 1013), calculate the value for the equilibrium constant for the following reaction: Cu(OH)2 (s) + 4NH3 (aq) ⇌ Cu(NH3)42+(aq) + 2OH -(aq) b. Use the value of the equilibrium constant you calculated in part a to calculate the solubility (in mol/L) of Cu(OH)2 in 5.0 M NH3. In 5.0 M NH3 the concentration of OH - is 0.0095 M.
The formation constant for [Cu(NH3)4]2+ is 5.00 × 1012. What is the equilibrium expression for this value? Group of answer choices Kf = 1/[[Cu(NH3)4]2+] Kf = [Cu2+][NH3]4/[[Cu(NH3)4]2+] Kf = [Cu2+][NH3]/[[Cu(NH3)4]2+] Kf = [[Cu(NH3)4]2+]/[Cu2+][NH3]4 Kf = [[Cu(NH3)4]2+]/[Cu2+][NH3] Kf = [[Cu(NH3)4]2+]