The formation constant for [Cu(NH3)4]2+ is 5.00 × 1012. What is the equilibrium expression for this...

Question

Question

The formation constant for [Cu(NH₃)₄]²⁺ is 5.00 × 10¹². What is the equilibrium expression for this value?

Group of answer choices

K_f = 1/[[Cu(NH₃)₄]²⁺]

K_f = [Cu²⁺][NH₃]⁴/[[Cu(NH₃)₄]²⁺]

K_f = [Cu²⁺][NH₃]/[[Cu(NH₃)₄]²⁺]

K_f = [[Cu(NH₃)₄]²⁺]/[Cu²⁺][NH₃]⁴

K_f = [[Cu(NH₃)₄]²⁺]/[Cu²⁺][NH₃]

K_f = [[Cu(NH₃)₄]²⁺]

Answer 1

Answer #1

formation constant for [Cu(NH₃)₄]²⁺ = 5.00 × 10¹²

balanced equation :

Cu2+ (aq) + 4 NH3 (aq) ------------> [Cu(NH₃)₄]²⁺

equilibrium expression :

Kf = [ [Cu(NH₃)₄]²⁺] / [Cu²⁺] [NH3]⁴

Answer :

K_f = [[Cu(NH₃)₄]²⁺]/[Cu²⁺][NH₃]⁴

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Answer 2

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