please help What is the approximate concentration of free Cu* ion at equilibrium when 1.57x102 mol...
1- What is the approximate concentration of free Cu2+ ion at equilibrium when 1.71×10-2 mol copper(II) nitrate is added to 1.00 L of solution that is 1.310 M in NH3. For [Cu(NH3)4]2+, Kf = 2.1×1013. [Cu2+] = ------ M
What is the approximate concentration of free Cu2+ ion at equilibrium when 1.22x102 mol copper(II) nitrate is added to 1.00 L of solution that is 1.210 M in NH3. For [Cu(NH3)4]. Ke-2.1x1013 (Cu?") - Submit Answer Determine ion concentration when separating ions in a mixture. A solution contains 1.58x102 M lead acetate and 1.58x10 ? Mmanganese(II) nitrate. Solid sodium sulfide is added slowly to this mixture. What is the concentration of lead ion when manganese(II)ion begins to precipitate? Solubility product...
Calculate concentration of species in a solution containing a complex ion. Close Problem In the presence of excess OH-, the Al3+(aq) ion forms a hydroxide complex ion, Al(OH)4-. Calculate the concentration of free Al3+ ion when 1.21×10-2 mol Al(CH3COO)3(s) is added to 1.00 L of solution in which [OH- ] is held constant (buffered at pH 12.60). For Al(OH)4-, Kf = 1.1×1033. [Al3+] = M
In the presence of excess OH-, the Al3+(aq) ion forms a hydroxide complex ion, Al(OH)4-. Calculate the concentration of free Al3+ ion when 1.32×10-2 mol Al(NO3)3(s) is added to 1.00 L of solution in which [OH- ] is held constant (buffered at pH 13.00). For Al(OH)4-, Kf = 1.1×1033. [Al3+] = ?M
Match: Substance Lewis base Bronsted-Lowry acid Arrhenius base Definition A. Provides H in water B. Provides OH in water C. Proton donor D. Proton acceptor E. Electron pair donor F. Electron pair acceptor Clear All Lewis Acid Lewis Base Can act as either a Lewis Acid or Lewis Base Neither a Lewis Acid or Lewis Base What is the approximate concentration of free Ag+ ion at equilibrium when 2.00x102 mol silver nitrate is added to 1.00 L of solution that...
1- In the presence of excess OH-, the Zn2+(aq) ion forms a hydroxide complex ion, Zn(OH)42-. Calculate the concentration of free Zn2+ ion when 1.32×10-2mol ZnSO4(s) is added to 1.00 L of solution in which [OH- ] is held constant (buffered at pH 12.40). For Zn(OH)42-, Kf = 4.6×1017. [Zn2+] = ------ M 2- What is the approximate concentration of free Hg2+ ion at equilibrium when 1.86×10-2 mol mercury(II) nitrate is added to 1.00 L of solution that is 1.310...
Calculate concentration of species in a solution containing a complex ion In the presence of excess OH, the Al3 (aq) ion forms a hydroxide complex ion, AIOH)4. Calculate the concentration of free Al3 ion when 1.46*102 mol Al(NO3)3(s) is added to 1.00 L of solution in which [OH-] is held constant (buffered at pH 12.60). For Al(OH)4, K?1.1x1033.
Calculate concentration of species in a solution containing a complex ion. In the presence of excess OH^ -, the Al^ 3+ (aq) ion forms a hydroxide complex ion, Al(OH)^ -_4. Calculate the concentration of free Al^ 3+ ion when 1.64 times 10^-2 mol Al(CH_3COO)_3(s) is added to 1.00 L of solution in which [OH^ -] is held constant (buffered at pH 12.10). For Al(OH)_4^ -, K_f = 1.1 times 10^33.
In the presence of excess OH-, the Zn2+(aq) ion forms a hydroxide complex ion, Zn(OH)42-. Calculate the concentration of free Zn2+ ion when 1.54×10-2 mol Zn(CH3COO)2(s) is added to 1.00 L of solution in which [OH- ] is held constant (buffered at pH 12.70). For Zn(OH)42-, Kf = 4.6×1017. [Zn2+] = M
Calculate the solubility of barium sulfate. BaSO4 in units of grams per liter. Ksp (BaSO4) = 1.1x10-10 solubility = AL The equilibrium concentration of chloride ion in a saturated lead chloride solution is M. In the presence of excess OH, the Ar+ (aq) ion forms a hydroxide complex ion. Al(OH)4 Calculate the concentration of free Ap+ ion when 1.56x10-mol Al(CH2C00)3(s) is added to 1.00 L of solution in which [OH-] is held constant (buffered at pH 12.10). For Al(OH)4, Ke=...