Question

Symmetric Cross Two rods of equal length L 1.90 m form a symmetric cross. The horizontal rod has a charge of Q = 100.0 C, and the vertical rod a charge of -Q -100.0 C. The charges on both rods are distributed uniformly along their length. Calculate the potential at the point P at a distance D 3.96 m from one end of the horizontal rod. 2.19 10 12 V Incorrect. Tries 3/20 Previous Tries Submit Answer

Answer 1

Rafshree PAGE NO. DATE Rloo C +Q L 1-10m D= 8.16 m L ++++-ttttt P K D We can Apit thiu in too tom + + + +++ + k D+L K L D Part(A) PauttB) potnlial due to paut LA) unit langth of And chauge L take Ar di elenunt m th road which i the a distance x at paint P The chauge af this clomat Tda da

Raishres Patential du to thu iment dve dy 4xto dVe 4Eo Pateatied Total d to tvey chaugal (2) 4xto - OFL & 4to 4Tt L Vt 9Xlo x 10D 1.9 (3.96+1-9 1-1 gx 103 x 100 X1-126 5-355 X10 V Vt 1 5.385 X1o" Va V

GATE ad Potential due to (B) Charge por unid langth 6 L dy het uu take small loment dy Tool. The chaug of th rod Dt dedy pt hetrod pant Pi Aymmchric about As the gn by The petntial due to elemend at Pi dy day dV- dy 4xto 2 4to log + It Dt) DE)

DATE V--9X109 100 396t 1-9 +N1+pe 21th 1-9 It (1-9/4)2 (31t19% 316t1% Xlo -2/2) V- O 825 f1og (1.212) -1og (0.8 9x lo 11 1-2 1L O.825 V- = - 1-9 25 X 1oV Total patential at! VTE VtV 5335-825)Xlo V VI 3.51 X1o V et