Question

Symmetric Cross Two rods of equal length L = 1.51 m form a symmetric cross. The horizontal rod has a charge of Q = 100.0 C, and the vertical rod a charge of -Q = -100.0 C. The charges on both rods are distributed uniformly along their length. Calculate the potential at the point P at a distance D = 2.56 m from one end of the horizontal rod. + + + + + + + + + + + + - DP -3.522E10 V

Answer 1

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1/2 L = 1.5100 0 = 100c -0 =-looc D=2.56m L Formula for potential at axial point of good is; vo kods (D+L) - 9x 109 x 100 xlo / 2.56 +1.51) 2.56 = 276.34 tolle 4109 vott Formula for potential art perpendicolor point of Godis Vo = KEO) and 2²+41+0)2 &LT 12+464 +12 -] - 9x to'xfloo) do 1513274/ 151725922157 4][150927414.51 +2:56)2 -1-51) – – 269.23 x 100 volt - 104 al potential at point P total & Uto + v.o. = 276.34x109 - 269.238109 Utotal = 7. 11x109 volt ! 1.51