Question

A point charge q is placed at a distance h from the center of a conducting sphere of radius R. An induced charge will be crea
0 0
Add a comment Improve this question Transcribed image text
Answer #1

b h law siing tu Come R2 h2- 2 Rh co md /2 (R2b 2 RbNoU, putrbal (22 h2-2Rh9 Due Ihangs VCR,O) T2 (p2+2-2Rb Nw euetory hoth potenhabs uro (R24 h.2Rhue) 2+2 Rbu (R2+ h2-2Rh0)r Rq2 (R262-2Rb co B) : q2 (R21h2-2Rhc0.0) for 2 CR2b2)e (R24) NOw, hucle in ee -2Rh coo) =9pi+ 62- 2Rhuoe 2 g2Rbcpe: eRh 22 2bCR2th2) 2 Thi guadrahe eg 7 h 2 R2th2 2 R2h2- 2h2 R 2h2 (R2 - h 2h . . Eith 2R2 2 h b (R2+h)-R h 2h2 2 h 2 h Not ponih bR 22nepje Peetpee Precuio Ao Recuch aout in t Comment sechon or duls uprote th answn wcun

Add a comment
Know the answer?
Add Answer to:
A point charge q is placed at a distance h from the center of a conducting...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Calculate the potential due to a point charge q in the presence of a conducting sphere...

    Calculate the potential due to a point charge q in the presence of a conducting sphere at constant potential V. Radius of conducting sphere is R. The point charge is situated at a distance b from the center of the sphere (b>R) ( Image charge for a grounded conducting sphere is given ; q' = -(Rq)/b and distance r'= R^(2)/b

  • Only need help with (d) = 0 ( [this point is away from 0] A conducting...

    Only need help with (d) = 0 ( [this point is away from 0] A conducting sphere of radius a is hollow and grounded (V = 0). A particle of charge q is a placed inside at a distance b from the center. We wish to find the potential anywhere inside the sphere. This problem can be solved with the image charge method. The image charge d' should be placed a distance b = from the center, so that the...

  • 1. A hollow conducting sphere of radius R has a charge Q placed on its surface....

    1. A hollow conducting sphere of radius R has a charge Q placed on its surface. A point charge Q1 is placed at a distance d> R from the center of the sphere. a) Using the method of superposition, find a combination of two image charges inside the sphere that result in the correct electric field and potential outside the sphere. b) What is the force between the sphere and the point charge? What is the force whern 0, and...

  • Example 3.2. A point charge q is situated a distance a from the center of a...

    Example 3.2. A point charge q is situated a distance a from the center of a grounded conducting sphere of radius R (Fig. 3.12). Find the potential outside the sphere. b q' V = 0 FIGURE 3.12 FIGURE 3.13

  • Method ofImages Griffiths shows (in Ex. 3.2) that the potential due to a point charge qa...

    Method ofImages Griffiths shows (in Ex. 3.2) that the potential due to a point charge qa distance a from the center of a grounded conducting sphere of radius R can be determined with the method of images by placing an image charge q'a distance b from the center of the sphere, between the center of the sphere and q, as shown. He shows that igure 3.12 Fipure 3.13 qq and b al Using the law of cosines and defining the...

  • A point charge q is located a distance r from the center of a conducting shell...

    A point charge q is located a distance r from the center of a conducting shell with inner radius R​1​​ and outer radius R​2​​. What is the electric potential at the center of the shell, assuming r <R​1​​? Question 7 A point charge q is located a distance r from the center of a conducting shell with inner radius R1 and outer radius R2. What is the electric potential at the center of the shell, assuming r< R1? Select the...

  • A conducting sphere of radius a has a total charge Q on it. A charge q...

    A conducting sphere of radius a has a total charge Q on it. A charge q is brought at a distance d from the center of the sphere (d > a). Using the method of images: (a) Find the electric potential V (r, θ) in the region r > a. (b) Find the surface charge density on the surface of the sphere. (c) Find the force on the charge q.

  • A point charge q is placed in the center of a solid dielectric sphere of radius R and permittivit...

    Pleasee I need the best answer! A point charge q is placed in the center of a solid dielectric sphere of radius R and permittivity e constant. Assume that the dielectric material of the sphere is linear and that the point charge in the center of the sphere is the only free charge a Determine the electrical displacement inside and outside the sphere. b. Determine the electric field inside and outside the sphere c. Determine the polarization vector using (1)...

  • An electric point charge of Q = 13.1 nC is placed at the center of a...

    An electric point charge of Q = 13.1 nC is placed at the center of a sphere with a radius of r = 32.1 cm. The sphere in this question is only a mathematical surface, it is not made out of any physical material. What is the electric flux through the surface of this sphere? Tries 0/12 This same point charge is now moved out from the center of the sphere by a distance of 17.9 cm. What is the...

  • Can someone carefully answer and explain the questions A and B in detail, please? 6.2 A charged conducting sphere (total charge Q) of radius b is placed into what is otherwise a region of uniform ele...

    Can someone carefully answer and explain the questions A and B in detail, please? 6.2 A charged conducting sphere (total charge Q) of radius b is placed into what is otherwise a region of uniform electric field E - Eoz a) At what position will you set V 0? b) Find the potential for r> b 6.2 A charged conducting sphere (total charge Q) of radius b is placed into what is otherwise a region of uniform electric field E...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT