Question

Write a functionthat calculates the first character in a string that exists more than twice in the stringand returns the index of that character or -1 if none exists.The program should prompt the user to enter an entire line including any whitespace as a string. The program then prints out the index and character that exists at least three times or a message “Not found” if all characters of the string have none or single duplicates.

In C++ please

For example:“Cheesy Feet”àe at index 2

“How are you? àNot found!

“It’sa great day.” àa at index 5

Answer 1

#include <iostream>
#include<string>
using namespace std;
void find(string c){
int flag=1;
for(int i=0;i<c.length();i++){
int count=0;
for(int j=0;j<c.length();j++){
if(c[i]==c[j])
count++;
}
if(count>=3){
cout<<c[i]<<" at index "<<i<<endl;
flag=0;
break;
}
  
}
if(flag)
cout<<"Not found\n";
}
int main()
{
char ch='y';
string arr;
while(ch=='y'||ch=='Y'){
cout<<"Enter name";
getline (cin, arr);
find(arr);
cout<<"do you want to continue press 'y'";
cin>>ch;
getline (cin, arr);
}
return 0;
}