Question

II Review Consider the truss shown in (Figure 1). Set Pi =5 kN. P. = 9 KN, Ps 13 kN. Part A Determine the force in member BC of the truss and state if this member is in tension or compression. Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension. HA OD? Fsc = 10.333 KN Submit Previous Answers Request Answer Figure 1 of 1 X Incorrect; Try Again; 4 attempts remaining Part B - Determine the force in member BE of the truss and state if this member is in tension or compression Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension. А в сі 3 m3 m3 m. ? G: HAR Value O a Units FBB =

Answer 1

Stepti P₂ = 15 kn Ay 3m P = 5KN in P2 = 9 KN 3m Replace supports by reaction, Ax , Ay are support reactions due to hinge Dy is support reaction due to roller support Step 2: Apply Equilibrum condition for whole truss. i Ev=0 Ay+ Oy = 5+9 Ay+ Oy = 14 D E H=0 | A = 13 KN » Dx 9 - 9x6 - 5x3 - 13x3 = 0

Substitute Oy - 103 Oy = 12 KN Oy in equation is Ay+12= 14 [Ay = 2 kN] Step 3: Cut the truss in such a way that the section should pass through more than 3 members. So required member forces are BC, BE and EF cut the section such that these are included. 13 KN ter 13KN Free Sin 45 LFBE --> FC045 Foc V5KN 2. His part 13 KN a 12 KN Applying equilibrium condition. Ev.o 2-5 + For Sin 45º = 0 Fr. 352 Fra: 4.24 26 kN Member is in Tension

žH=0 13+ For + FBE Cos 45 + Foc -13 = 0 FER + 352 x 1 / + FBc :o Fer + Fec :-3 kN) – (a) E MB=0 = 0 Ex3 + 13×3 + 2x3 FEF -45 FER = -15 KN member is in Compression Substitute in Equation (a). - 15 + FBc =-3 For = 12 kN → member is in Tension Summery: The required member forces are FBC = 12 KN FBE - 4.243 KN For = - 15kN
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