Question

FIGURE 1.2 Given: m 2 1 and two positive numbers each containing m digits, an-am-2.... and bm-bm-2...be Wanted: Cm Cm-1 Cm-2... Cor where Cm Cm-Cm-2... Co = (am-1 am-2...an) + (bm-1 bm-2...bd Algorithm: Step 1 Set the value of carry to O Step 2 Set the value of i to 0 Step 3 While the value of i is less than or equal to m – 1, repeat the instruc- tions in Steps 4 through 6 Step 4 Add the two digits a, and b, to the current value of carry to get c. Step 5 If c, z 10, then reset cto (c; – 10) and reset the value of carry to 1; otherwise, set the new value of carry to O Step 6 Add 1 to i, effectively moving one column to the left Step 7 Set Con to the value of carry Step 8 Print out the final answer, Cm Cm-1 Cm-2...Co Step 9 Stop

do in java

Answer 1

CODE:

import java.util.*;
class Sum{
public static void main(String[] args) {
Scanner console = new Scanner(System.in);
System.out.print("Enter Value m: ");
int m = console.nextInt(); // Taking input m (No of digits)
System.out.print("Enter Value a: ");
int a = console.nextInt(); //Taking input value a
System.out.print("Enter Value b: ");
int b = console.nextInt(); //Taking input value a
int carry=0; // set carry to 0
int i=0; // set i to 0
// ci is for storing ci value
// c is for storing finall value
// d is for increment the digits length of c so that we can add every ci to c
int j,ci=0,c=0,d=1; // Declaring required variables
while(i<= m-1){ // Loop while i <= m-1
ci = carry + (a%10) + (b%10); // Adding carry and ai and ci
if(ci>=10){ //when ci > 1=
ci = ci -10; //Subtract ci-10
carry = 1; // set carry = 1
}
else
carry = 0; // else set carry = 0
c = ci*d+c; // add ci value to c
a = a/10; // removing ai digit
b = b/10; // removing bu digit
d= d*10; // increment d
i++; // incrementing i fot next iteraions
}
c = carry*d+c; // set cm to the value of carry
System.out.println("Final answer c is : "+c); // printing value c

}
}

CODE ATTACHMENTS:

OUTPUT:

1 import java.util.*; class Sum{ public static void main(String[] args) { Scanner console = new Scanner(System.in); System.out.print("Enter Value m: "); int m = console.nextInt(); // Taking input m (No of digits) System.out.print("Enter Value a: "); int a = console.nextInto; //Taking input value a System.out.print("Enter Value b: "); int b = console.nextInt(); //Taking input value a int carry=0; // set carry to o int i=0; // set i to o // ci is for storing ci value Il c is for storing finall value // d is for increment the digits length of c so that we can add every ci to c. int j,ci=0,c=0,d=1; // Declaring required variables while(i<= m-1) { // Loop while i <= m-1 ci = carry + (a%10) + (b%10); // Adding carry and ai and ci if(ci>=10){ //when ci > 1= ci = ci -10; //Subtract ci-10 carry = 1; // set carry = 1, else carry = 0; // else set carry = 0 c = ci*d+c; // add ci value to C a = a/10; // removing ai digit b = b/10; // removing bu digit d= d*10; // increment di i++; // incrementing i fot next iteraions c = carry*d+c; // set cm to the value of carry System.out.println("Final answer c is : "+c); // printing value c 32 33 } 34 }

Enter Value m: 3 Enter Value a: 569 Enter Value b: 784 Final answer cis : 1353

ci is for storing ci value
c is for storing finall value
d is for increment the digits length of c so that we can add every ci to c

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