How many grams of a slightly soluble salt having the formula AX3, with a molecular 1....
1-4 please help 7 points possible Last Name First Name 1 x 1031. It dissociates in water The slightly soluble salt fluorapatite, Cas(POa)3F, has a Ksp according to the following equation: Cas(PO4)3Fi 5Ca2 3PO F 1. Write the Ksp equation for this process: Ksp Calculate the equilibrium concentrations of Ca, PO, and F. 2. a. [Ca2]= b. [PO]= c. [F]= How many grams of fluorapatite will dissolve in 1L of water? 3. 4. The solubility of the related salt hydroxyapatite,...
EXPERIMENT 7: DETERMINATION OF KS FOR A SLIGHTLY SOLUBLE SALT QUESTIONS Average Ksp = 3.17x10-12 1. Based on the value of the Key that you calculated for AgeCrO4, how many grams of Ag2 CrO 4 will dissolve per Liter of solution? 2. In the second part of the experiment, why was the [AgNO3l larger than the (K,CrO4l? What would have happened if they had been the same?
1. How is the molar solubility of a slightly soluble salt affected by the addition of an ion common to the salt equilibrium? 2. A 3.11 mL volume of a standardized 0.0025 M HCl solution titrated 25.0 mL of a saturated Mg(OH)2 solution to the methyl orange endpoint. Calculate the Ksp of Mg(OH)2. 3. If the endpoint in the titration of a saturated Ca(OH)2 solution with a standardized HCI solution is surpassed, will the reported Kap of Ca(OH)2 be reported...
Consider the following data for questions A-F: two solutions of an unknown slightly soluble salt, A(OH)2, we're allowed to equalibrate – one at 25°C and the other at 80°C. A 15 mL aliquot of each solution is titrated with 0.240 M hydrochloric acid. 8.30 mL of the acid is required to reach the endpoint of a titration at 25°C, while 75.07 mL are required for the 80°C solution. What is the Ksp at 80° C? Exp 10 Solubility and Thermodynamics)...
Consider the following data for questions A-F: two solutions of an unknown slightly soluble salt, A(OH)2, were allowed to equilibrate- one at 25°C and the other at 80°C. A 15 mL aliquot of each solution is titrated with 0.240 M in HCl. 8.30 mL of the acid is required to reach the end point of the titration at 25°C, while 75.07 mL are required for the 80°C solution. Review Contas Periodic Tate Consider the following data for questions A-F: Two...
The nonvolatile, nonelectrolyte sucrose , C12H22O11 (342.3 g/mol), is soluble in water H2O. How many grams of sucrose are needed to generate an osmotic pressure of 3.56 atm when dissolved in 227 ml of a water solution at 298 K. grams sucrose
1. “Salt” (NaCl) is known to be readily soluble in water, however there is a limit to its solubility. The solubility of salt in water at 25° C is 35.9 g/100 mL a. Explain what the value 35.9 g/100 mL means. . b. Write this value as two conversion factors. c. What minimum volume of water would be necessary to dissolve 2.2 kg of salt? 2. A pair of students forgets to precipitate the carbonate ions in their leaf compost...
could you do all three, please " How many grams of salt are present in 13.5 g of a 2.56 % salt solution? How many grams of sugar and how many grams of water are needed to prepare 250.00 g ofa 1.70 % w/w sugar solution? . 17.5 g of sugar is dissolved in 200.0 g of water. What is the percent by mass concentration of the sugar solution?
How many grams of this substances will dissolve in 100 mL of cold water?(NH4)2SeO4
Consider the following data: Two solutions of an unknown slightly soluble salt, A(OH)2, were allowed to equilibrate--one at 25 degrees Celsius and the other at 80 degrees Celsius. A 15.00 mL aliquot of each solution is titrated with 0.250 M HCl. 6.49 mL of the acid is required to reach the endpoint of the titration at 25 degrees Celsius, while 63.07 mL are required for the 80 C solution. 1. Assuming that the change in enthalpy is negligible over this...