Question

Please label and interpret the following HNMR peaks of an unknown compound. Be sure to include the complete calculation of the peak integration, splitting patterns, and identify the chemical formula of the unknown compound. Also, there is an impurity peak at 3.4 ± 0.2 ppm.

No title BRUKER Carzent Data Paxaetera 20290307 SWH F IDRES o.220503 sec 0.0L500000 sec 400-1331 926 M 22 - Prscessing pazane

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Answer #1

1H NMR analysis

quartet at 4.05 ppm is due to methylene proton (CH2) attached to oxygen (q, 4.06 ppm, 2H)

singlet at 2 ppm is due to methyl proton (CH3) attached to carbonyl group (s, 2.00 ppm, 3H)

triplet at 1.23 ppm is due to methyl group (CH3) attached to methylene group (t, 1.23 ppm, 3H)

therefore the structure of the compound is

H3C Нас CH3 ethyl acetate

the impurity at 3.4 ppm is might be due to acetic acid or ethanol

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