Question

< Question 11 of 22 At a certain temperature, a 25.0-L container holds four gases in equilibrium. Their masses are 3.5 g SO 4.6 , 25.03 N,, and 0.98 g NO. What is the value of the equilibrium constant at this temperature for the reaction of SO, with N20 to form SO, and N7 Make sure you balance the reaction using the lowest whole number coefficients K =

Answer 1

given that Volume of container = 25.0L mass of so3 = 3.5 g mass of so2 = 4.69 mass of do = 25.09 mass off dzo = 0.98g we know that concentration of substance can also expressed in g/ mass of substance(a) volume of containes ncentration of sogl[soz]) = 3.58 -0.149 25.02 = 0.149 centration of so2([soz]) = 4.69 201849 25.0L concentration of dalla 25.09 25.02 = log/L Concentration of doo ([dzo]) = 0.988 = 0.0392 g 25.01 = 0.03929 we know that reaction between place as follows: son and Hoo takes SO2(g) + da da) soz (g) + d₂ (8) Above reaction is balanced.. Equilibrium constant (Kc) for above reaction can be expressed as follows: [sog] [Na] [502] [deo] where, [sog] [dz], [502], [dzo] equilibrium concentration of products and reactants respectively. Kc =

le 26600 = [ on] 716 0.1 le h o = = [ZN] [eos ] Menol. = [2os

ko - [sog] [dz] [soa] [dzo] - (0.1482) (108) (0.184912) (0.039284 Kc = 0.14 - 0.0072128 19.4 Hence, Kc = 19.41 An Answer