Question

The current flowing into a box is given by the waveform shown below. Calculate the following quantities (a) the amount of charge which has entered the box at t-1 sec, t-3 sec andt=4.5 sec (b) the power absorbed by the box at t 1 sec, 2.5 sec, 4.5 sec and 5.5 sec. and (c) the amount of energy absorbed by the box between 0 and 6 sec. COT. )(A) 21 1- 2 V 6 Figure Pi.15 The charge flowing in a box is shown below. Sketch the power and energy absorbed by the box. P1.4 q) (C) 2- 1 7 V (s) 6 5 2 3

Answer 1

Each part is done one by one and all formulae are given.

q = integral i dt rightarrow area under the i-t curve p = V i E = integral p dt = integral V i dt = V integral i dt = V q [V is constant here] = 2V Therefore a) t = 1 implies q = 1 times 2 = 2C t = 3 implies q = 2 + (3 - 2) times (- 1) = 1C t = 4.5 implies q = 2 + (4 - 2) times (- 1) = . b) t = 1 implies P = 2 times 2 = 4 W t = 2.5 implies P = 2 times - 1 = -2W t = 4.5 implies P = 2 times 0 = 0 t = 6 implies P = 2 times 1 = 2 W c) q = 2 times 1 + 2 times (- 1) + 1 times 1