Question

2. Complete this table. Show your work for NH3. Assume there is no vibrational internal energy. Calculate the energy assuming 1 mol of gas and a temperature of 298,15 K. Look up the experimental values in the Handbook of Chemistry and Physics (8 marks. Translational Rotational Vibrational Equipartition Experimental Degrees of Degrees of Degrees of Cp.m Freedom Freedom Freedom (UK-mol (JK-mol He (g) NO (8) NH: (g) Сpn

Answer 1

☺ @ Hel Meno atomic Only tocmlational degree of freedom , Ny = 3 (3, 4, z direction) Rotational degree of free down, NR = 0 Vibrational digree of freedom, Ny=0 Mare, No vibrational internal energy. Each degree of freedom contikitus / kept to evergy of system. * Quly Teamslational & Rotational U= 3x2 kg T +0+0 = RAT = nRT = {RT (no licle) (kg = nR) Cvs (F), = QR 8314 J K' upti = 12.471 J k wohet Cras contant Boltzmown constant [Cp-cv = R Cp= R + Cy Cp= 8314 J kil melal + 12.471 J Kalweden! Op = 20785 Jkt male? No diatomic, linear NT= 3 (3,4, 2) , NR = 2 (2,4) , Ny = 3N-5 = 4 Us 3x4 kg'T + 2x4 *T + 4x0 = 5 kg T = NRT = {RT cve ses Cp = R4cy - ZR = 7x8.314 = 29.099 Jktuelt

Ni triatonic, Now Linear M4= 3 (7,8,2) , NR= 3 (x,y,z) Ny = 3N-6 - 6 U= 3x} het + 3x + kot + 6x0 3 *1 3nRT=3RT Cu= ($4), = SR CD= R + CV = AR = 4*8.314 I ku malit33.256 I kl male Solution Molecule Toonelational Rolational Vibratimal Exfovincial Helg) و Equi fartaren (TK'weli") 20-785 29.099 33256 NO (8) MMM 2 Cp (1x lue") 20.760 29.899 37 298 N4 (3) ادا