Find the equivalent classes of the relation RL for
the L defined in 1.46 part (a). Recall that for any language L, not
necessarily a regular language, we defined the equivalence relation
RL on
Σ* as follows: xRLy iff ∀z ∈ Σ* , [xz ∈ L ⇐⇒ yz ∈
L].
1.46) Prove that the following languages are not regular. You may use the pumping lemma and the closure of the class of regular languages under union, intersection, and complement.
a. {0n1m0n | m,n ≥ 0}
Find the equivalent classes of the relation RL for the L defined in 1.46 part (a)....
Prove the following language is not regular (you may use pumping lemma and the closure of the class of regular languages under union, intersection, and complement.): (w | w ∈ {0,1}* is not a palindrome} Please show work/explain. Thanks.
1. (Non-regular languages) Prove that the following languages are not regular. You may use the pumping lemma and the closure of the class of regular languages under union, intersection, complement, and reverse (b) L2 = { w | w ∈ {0, 1}* is not a palindrome }. A palindrome is a string that reads the same forward and backward
Question 1: Every language is regular T/F Question 2: There exists a DFA that has only one final state T/F Question 3: Let M be a DFA, and define flip(M) as the DFA which is identical to M except you flip that final state. Then for every M, the language L(M)^c (complement) = L( flip (M)). T/F Question 4: Let G be a right linear grammar, and reverse(G)=reverse of G, i.e. if G has a rule A -> w B...