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Part A It K = 4.1x10-2 for PCL (9) + Cl2(g) = PCs (9) at 520 K, what is the value of K, for this reaction at this temperature
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Answer #1

T = 520 K

Δ n = number of gaseous molecule in product - number of gaseous molecule in reactant

Δ n = -1

use:

Kp= Kc (RT)^Δ n

Kp = 4.1*10^-2*(0.08206*520.0)^(-1)

Kp = 9.608*10^-4

Answer: 9.6*10^-4

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