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QUESTION 9 Find the value and uncertainty for the following expressions, where the values in parentheses represent the standa
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dus general Rule. R= x. Y de = 1R1. J( + (4994 Y = (10.2.74 + 009) 470-009680.003)X 9. 33400) Solution Rz o ovog X 2033 = 0.0e due general Rules he x +y + 2 dR = √ (dx)² + (dy)² + (dz)? • Solution y = (0.274 +0.040) + (60021 + 0.008) ys 0.274 +0.02)

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