Answer:
Given test statistic = 1.91
Given degrees of freedom= 20
This is an upper tail test.
Critical values at 0.01 level = 2.528
Test statistic is < critical value.
Ho is not rejected at 0.01 level of significance.
Therefore we write the p value as : P > 0.01
Excel Analysis for the data:
Pooled-Variance t Test for the Difference Between Two Means |
|
(assumes equal population variances) |
|
Data |
|
Hypothesized Difference |
0 |
Level of Significance |
0.01 |
Population 1 Sample |
|
Sample Size |
10 |
Sample Mean |
6.54 |
Sample Standard Deviation |
2.65 |
Population 2 Sample |
|
Sample Size |
13 |
Sample Mean |
4.75 |
Sample Standard Deviation |
1.85 |
Intermediate Calculations |
|
Population 1 Sample Degrees of Freedom |
9 |
Population 2 Sample Degrees of Freedom |
12 |
Total Degrees of Freedom |
21 |
Pooled Variance |
4.9654 |
Standard Error |
0.9373 |
Difference in Sample Means |
1.7900 |
t Test Statistic |
1.9098 |
Upper-Tail Test |
|
Upper Critical Value |
2.5176 |
p-Value |
0.0350 |
Do not reject the null hypothesis |
wondering how to find the P-value from the data given. I have t-tables and diffewnt tables...
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