a)
Left tailed test
b)
Test statistic,
z = (pcap - p)/sqrt(p*(1-p)/n)
z = (0.0719 - 0.09)/sqrt(0.09*(1-0.09)/278)
z = -1.05
c)
P-value Approach
P-value = 0.1463
d)
Null Hypothesis, H0: p = 0.09
As P-value >= 0.1, fail to reject null hypothesis.
A certain drug is used to treat asthma in a clinical trial of the shows results...
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