Question

How do I solve it what do I need to do to get the answer

26, A certam radiou tive decay process 'fint order) is 45% complete in 66 secon s. what is the half ase for this process? HINTS: Firstsolve for rate constant. Assume initial concentration of 100M. ~1n(ト0.45) GS し3.3 seconds b. 56.4 seconds С. 81 ,7 seconds d 75.3 seconds

Answer 1

Radio active decay follows the 1st order kinetics Initial concentrati on of the reactantA Final concentration of the reactant after time , [A]t =[4-45%A0 = 55%).A. = 0.5JA]0 time elapse, t 65s According tolst order Kinetics , k- -lrn 65 s 0.55LA 0.0092 s -1 0.693 Half life period, 4 = 0.693 0.0092 s 75.3 s