2. Random variable Z has the standard normal distribution. Find the following probabilities a): P[Z >...
1. Given that z is a standard normal random variable, compute the following probabilities. a. P(Z < 1.38) b. P(z 2 1.32) c. P(-1.23 Sz5 1.23)
(1 point) Find the following probabilities for the standard normal random variable z. (a) P(-0.81 <<0.42) (b) P(-1.14 <z < 0.5) (c) P(Z < 0.69) a (d) P(Z > -0.6)
Find these probabilities for a standard normal random variable Z. Be sure to draw a picture to check your calculations. Use the normal table or software, (a) P(Z < 1.2) (d) P(Z >0.4) (b) P(Z > -1) (e) P(-1SZs1.2) (c) P(|<1.5)
Find a value of the standard normal random variable z, call it zo, such that the following probabilities are satisfied. a. P(zszo)= 0.0185 b. P(-20 szszo) = 0.95 c. P(-20 szszo) = 0.99 d. P(-20 szszo)=0.8646 e. P(-20 Sz50) = 0.2501 f. P(-2<z<zo)= 0.9612 g. P(z>zo) = 0.5 h. P(z szo)= 0.0076
Find a value of the standard normal random variable z, call it zo such that the following probabilities are satisfied. a. P(z Szo)=0.0473 b. P(- zo szszo)=0.99 c. P(-20 sz szo)=0.95 d. P(-20 52520) = 0 8358 e. P(-20 Sz50)= 0.2612 f. P(-2<z<zo)=0.9503 g. P(z>20)=0.5 h. PZSzo) = 0.0027
A) 0.7995 11. If Z is a standard normal variable find the probabilities of a) P(Z <-0.35)- @w B) 0.3982 C) 1.2008 D) p.4013 (2 points) b) P(0.25s Z<1.55) (3 points) c) P(Z > 1.55) (2 points) 12. Assume that X has a normal distribution with mean deviation .5. Find the following probabilities: 15 and the standard a) P(X < 13.50)- 3 points). b) P (13.25 <X < 16.50)- (5 points). B) 0 2706 C0 5412 D) 1.0824 A mountuin...
Find a value of the standard normal random variable z, call it 20, such that the following probabilities are satisfied. a. P(zszo)=0.0502 b. P(-2o Szszo)=0.99 c. P(-zo szszo)=0.90 d. P(- zo szszo) = 0.8062 e. P(-Zo Szs 0) = 0.2593 f. P(-3<z<zo)=0.9654 g. Plz>20) = 0.5 h. Plz szo) = 0.0088
Suppose that a random variable ?z has a standard normal distribution. Use a standard normal table such as this one to determine the probability that ?z is between −0.67 and 0.33. Give your answer in decimal form, precise to at least three decimal places. ?(−0.67<?<0.33)=P(−0.67<z<0.33)=
9. Compute the following probabilities using your calculator. Assume Z is a standard normal random variable. Round all answers to three decimal places. A. P(0<Z<2.3)P(0<Z<2.3)= B. P(−1.7<Z<0.15)P(−1.7<Z<0.15)= C. P(Z>−1.2)P(Z>−1.2)= 10. Find the following probabilities for the standard normal random variable zz: Round answers to three decimal places. (a) P(z≤1.31)=P(z≤1.31)= (b) P(z>−0.25)=P(z>−0.25)=
[6] Let z be a standard normal random variable. Compute the following probabilities. P(–1.23 ≤ z ≤ 2.58) P(z ≥ 1.32) P(z ≥ –1.63) P(z ≤ –1.38) P(–1.63 ≤ z ≤ –1.38) P(z = 2.56) I don't understand how z scores compute ?? I have looked at Z score tables in the book and I still don't understand