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1. Given that z is a standard normal random variable, compute the following probabilities. a. P(Z < 1.38) b. P(z 2 1.32) c. P

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Solution Given that using standard normal table a) Plze 1.38) = probability = 0.9162 0.9162 DP (z=1.32) lp (z 41.32) =I- 0.90

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