Question

question 2

1. What is the % error? The actual formula is H2C204: 2H2O. 2. A CHEM 101 student has 0.467 g of KHP, how many mL of your NaOH wil require to titrate this sample?

Answer 1

2)

HKC8H4O4 + NaOH --->NaKC8H4O4 + H2O

Moles of KHP = mass of KHP / Molar mass of KHP = 0.467/204.22 = 0.002287 moles

From reaction;

Mole ratio of KHP to NaOH = 1 : 1

So, moles of KHP = moles of NaOH = 0.002287 moles

Volume of NaOH in liters (V) = Moles/molarity of NaOH

Let M is the molarity of NaOH. Then,

V = 0.002287/M liters

V in ml = 0.002287*1000/M = 2.287/M ml ....Answer

We just need to molarity (concentration) of NaOH which is not mentioned in question. Let me know if any doubts.