Homework Answers
ΔHo = -1269.8 KJ
ΔSo = -364.6 J/K
= -0.3646 KJ/K
T= 24.0 oC
= (24.0+273) K
= 297 K
use:
ΔGo = ΔHo - T*ΔSo
ΔGo = -1269.8 - 297 * -0.3646
ΔGo = -1162 KJ
Answer: -1162 KJ
Add Answer to:
n Review | Constants Periodic Table 2 Ca(s) + O2(g) + 2Cao(s) AH = -1269.8 kJ;...
2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K For this problem, assume that all reactants...
2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn=
-1269.8 kJ; ΔS∘rxn= -364.6 J/K For this problem, assume that all
reactants and products are in their standard states. You may want
to reference (Pages 811 - 815) Section 18.6 while completing this
problem.
<Chapter 18 Homework Exercise 18.46 - Enhanced - with Feedback 20 of 37 Review I Constants I Periodic Table 2Ca(s)02(g)2CaO(s) AH 1269.8 kJ; AS 364.6 J/K Part A For this problem, assume that all reactants and products are in their standard states....
2Ca(s) + O2(g) → 2CaO(s) A Hix = -1269.8 kJ: ASP = -364.6J/K Calculate the free...
2Ca(s) + O2(g) → 2CaO(s) A Hix = -1269.8 kJ: ASP = -364.6J/K Calculate the free energy change for the reaction at 20°C Express your answer using four significant figures. For this problem, assume that all reactants and products are in their standard states. You may want to reference (Pages 811-815) Section 18.6 while completing this problem. VALD ROO? AG = Submit Request Answer Part B Is the reaction spontaneous? spontaneous nonspontaneous Submit Request Answer
2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K You may want to reference (Pages 706...
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2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K For this problem, assume that all reactants...
2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K For this problem, assume that all reactants and products are in their standard states. Calculate the free energy change for the reaction at 17 ∘C. Express your answer using four significant figures. ΔG = _____kJ
2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K For this problem, assume that all reactants...
2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K For this problem, assume that all reactants and products are in their standard states. Calculate the free energy change for the reaction at 29 ∘C. Express your answer using four significant figures. Part A ΔG = ______ kJ Part B Is the reaction spontaneous? spontaneous OR nonspontaneous
Consider the following reaction: 2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K Assume that all...
Consider the following reaction: 2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K Assume that all reactants and products are in their standard states. Calculate the free energy change for the reaction at 34 ∘C. Express your answer using four significant figures.
Consider the following reaction: 2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K Calculate the free...
Consider the following reaction: 2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K Calculate the free energy change for the reaction at 32 ∘C.
2Ca(s)+O2(g)→2CaO(s) ΔrH∘= -1269.8 kJmol−1; ΔrS∘= -364.6 JK−1mol−1 Calculate the Gibbs energy change for the reaction at...
2Ca(s)+O2(g)→2CaO(s)
ΔrH∘= -1269.8 kJmol−1; ΔrS∘= -364.6 JK−1mol−1
Calculate the Gibbs energy change for the reaction at 24 ∘C.
Express your answer using four significant figures.
2Ca(s) + O2 (g) → 2CaO(s) Δ,Ho =-1269.8 kJ mol 1: Δ,S":-3646 J K 1 mol 1 Part A Calculate the Gibbs energy change for the reaction at 24 °C. Express your answer using four significant figures. kJ mol 1 Submit Previous Answers Request Answer
Consider the following reaction: 2Ca(s) + O_2(g) rightarrow 2CaO(s) Delta H_rxn = -1269.8 kJ; Delta S_rxn...
Consider the following reaction: 2Ca(s) + O_2(g) rightarrow 2CaO(s) Delta H_rxn = -1269.8 kJ; Delta S_rxn degree = -364.6 J/K Assume that all reactants and products are in their standard states. Part A Calculate the free energy change for the reaction at 28 degree C. Part B Is the reaction spontaneous? spontaneous nonspontaneous
Review | Constants I Periodic Table Consider the reaction at 298 K: 2H, S(g) + SO2(g)...
Review | Constants I Periodic Table Consider the reaction at 298 K: 2H, S(g) + SO2(g) →3S(s, rhombic) + 2H2O(g) AG = -102 kJ Part A You may want to reference (Pages 826 - 829) Section 18.9 while completing this problem. Calculate AG an under the seconditions: PAS PsO Pilo 1.95 atm 1.56 atm 0.0140 atm
2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn=
-1269.8 kJ; ΔS∘rxn= -364.6 J/K For this problem, assume that all
reactants and products are in their standard states. You may want
to reference (Pages 811 - 815) Section 18.6 while completing this
problem.
<Chapter 18 Homework Exercise 18.46 - Enhanced - with Feedback 20 of 37 Review I Constants I Periodic Table 2Ca(s)02(g)2CaO(s) AH 1269.8 kJ; AS 364.6 J/K Part A For this problem, assume that all reactants and products are in their standard states....
2Ca(s) + O2(g) → 2CaO(s) A Hix = -1269.8 kJ: ASP = -364.6J/K Calculate the free energy change for the reaction at 20°C Express your answer using four significant figures. For this problem, assume that all reactants and products are in their standard states. You may want to reference (Pages 811-815) Section 18.6 while completing this problem. VALD ROO? AG = Submit Request Answer Part B Is the reaction spontaneous? spontaneous nonspontaneous Submit Request Answer
2Ca(s)+O2(g)→2CaO(s)
ΔrH∘= -1269.8 kJmol−1; ΔrS∘= -364.6 JK−1mol−1
Calculate the Gibbs energy change for the reaction at 24 ∘C.
Express your answer using four significant figures.
2Ca(s) + O2 (g) → 2CaO(s) Δ,Ho =-1269.8 kJ mol 1: Δ,S":-3646 J K 1 mol 1 Part A Calculate the Gibbs energy change for the reaction at 24 °C. Express your answer using four significant figures. kJ mol 1 Submit Previous Answers Request Answer
Consider the following reaction: 2Ca(s) + O_2(g) rightarrow 2CaO(s) Delta H_rxn = -1269.8 kJ; Delta S_rxn degree = -364.6 J/K Assume that all reactants and products are in their standard states. Part A Calculate the free energy change for the reaction at 28 degree C. Part B Is the reaction spontaneous? spontaneous nonspontaneous
Review | Constants I Periodic Table Consider the reaction at 298 K: 2H, S(g) + SO2(g) →3S(s, rhombic) + 2H2O(g) AG = -102 kJ Part A You may want to reference (Pages 826 - 829) Section 18.9 while completing this problem. Calculate AG an under the seconditions: PAS PsO Pilo 1.95 atm 1.56 atm 0.0140 atm
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