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Exercise 18.46 Enhanced with Feedback Consider the following reaction: 2Ca(s) O2 (g) 2CaO(s) 1269.8 kJ AS -364.6 J/K Assume that all reactants and products are in their standard states. You may want to reference (D page)Section 18.6 while completing this problem. Part A Calculate the free energy change for the reaction at 28 C. Express your answer using four significant figures. AG Submit My Answers Give Up Part B Is the reaction spontaneous? O spontaneous nonspontaneous Submit My Answers Give Up kJ
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Answer #1

Expression for free energy \Delta Gcan be written as follows:

AH-TAS

Substitute values of -1269.8 kJ for \Delta H, -0.3646 kJ/K for \Delta S and (28+273) K for T.

\Delta G = (-1269.8 kJ ) - (28+273) K(-0.3646 kJ/K)

\Delta G = -1160.1 kJ

Therefore, change in free energy is -1160.1 kJ

Nonspontaneous reaction have positive \Delta G and spontaneous reaction have negative \Delta G.

Since, \Delta G of given reaction is negative. The reaction is spontaneous.

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Consider the following reaction: 2Ca(s) + O_2(g) rightarrow 2CaO(s) Delta H_rxn = -1269.8 kJ; Delta S_rxn...
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