Expression for free energy can be written as follows:
Substitute values of -1269.8 kJ for , -0.3646 kJ/K for and (28+273) K for .
= (-1269.8 kJ ) - (28+273) K(-0.3646 kJ/K)
= -1160.1 kJ
Therefore, change in free energy is -1160.1 kJ
Nonspontaneous reaction have positive and spontaneous reaction have negative .
Since, of given reaction is negative. The reaction is spontaneous.
Consider the following reaction: 2Ca(s) + O_2(g) rightarrow 2CaO(s) Delta H_rxn = -1269.8 kJ; Delta S_rxn...
2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K For this problem, assume that all reactants and products are in their standard states. Calculate the free energy change for the reaction at 29 ∘C. Express your answer using four significant figures. Part A ΔG = ______ kJ Part B Is the reaction spontaneous? spontaneous OR nonspontaneous
2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K For this problem, assume that all reactants and products are in their standard states. You may want to reference (Pages 811 - 815) Section 18.6 while completing this problem. <Chapter 18 Homework Exercise 18.46 - Enhanced - with Feedback 20 of 37 Review I Constants I Periodic Table 2Ca(s)02(g)2CaO(s) AH 1269.8 kJ; AS 364.6 J/K Part A For this problem, assume that all reactants and products are in their standard states....
Consider the following reaction: 2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K Assume that all reactants and products are in their standard states. Calculate the free energy change for the reaction at 34 ∘C. Express your answer using four significant figures.
Consider the following reaction: 2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K Calculate the free energy change for the reaction at 32 ∘C.
2Ca(s) + O2(g) → 2CaO(s) A Hix = -1269.8 kJ: ASP = -364.6J/K Calculate the free energy change for the reaction at 20°C Express your answer using four significant figures. For this problem, assume that all reactants and products are in their standard states. You may want to reference (Pages 811-815) Section 18.6 while completing this problem. VALD ROO? AG = Submit Request Answer Part B Is the reaction spontaneous? spontaneous nonspontaneous Submit Request Answer
2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K For this problem, assume that all reactants and products are in their standard states. Calculate the free energy change for the reaction at 17 ∘C. Express your answer using four significant figures. ΔG = _____kJ
2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K You may want to reference (Pages 706 - 709) section 17.5 while completing this problem. Part A Calculate the free energy change for the reaction at 15 ∘C. Express your answer using four significant figures.
2Ca(s)+O2(g)→2CaO(s) ΔrH∘= -1269.8 kJmol−1; ΔrS∘= -364.6 JK−1mol−1 Calculate the Gibbs energy change for the reaction at 24 ∘C. Express your answer using four significant figures. 2Ca(s) + O2 (g) → 2CaO(s) Δ,Ho =-1269.8 kJ mol 1: Δ,S":-3646 J K 1 mol 1 Part A Calculate the Gibbs energy change for the reaction at 24 °C. Express your answer using four significant figures. kJ mol 1 Submit Previous Answers Request Answer
n Review | Constants Periodic Table 2 Ca(s) + O2(g) + 2Cao(s) AH = -1269.8 kJ; ASX = -364.6 J/K Part A For this problem, assume that all reactants and products are in their standard states. You may want to reference (Pages 811 - 815) Section 18.6 while completing this problem. Calculate the free energy change for the reaction at 24 °C. Express your answer using four significant figures. V AEQ O 2 ? AG = Submit Previous Answers Request...
Consider the reaction: FeO (s) + Fe (s) + O_2 (g) rightarrow Fe_2O_3 (s) Given the following table of thermodynamic data, Substance Delta H_f degree S degree FeO (S) -271.9 kJ/mol 60.75 J/mol - K Fe (s) 0 27.15 O_2 (g) 0 205.0 Fe_2O_3 (S) -822.16 89.96 determine the temperature (in degree C) above which the reaction is nonspontaneous.