Question

.Metro by T-Mobile LTE 12:53 AM 44% 4 Question Chemical Stoichiometry Unanswered If 80.0 grams of oxygen gas is consumed with a stoichiometric equivalent of aluminum metal, how many grams of aluminum oxide (molar mass = 102 g/ mol) would be produced? Type your response 4 Al(s) + 3 0,09) - 2 A1,0, (s) 2 attempts left. Submit

Answer 1

170 grams of Al2O3

Balanced chemical reaction is:

4 Al (s) + 3 O2 (g) -----> 2 Al2O3 (s)

moles of oxygen reacted = (80 g) / (32 g/mol) = 2.5 mol

Here; Al reacted in stoichiometric amount.

So;

No. of moles of Al2O3 produced = (2 / 3) x 2.5 mol = 1.667 ol of Al2O3

weight of Al2O3 produced = (1.667 mol) x (102 g/mol) = 170 grams of Al2O3