Please help if you know how to solve any of the questions 5,6,7, and 8.
Question 8 is not in the picture.
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Please help if you know how to solve any of the questions 5,6,7, and 8. 5....
please solve 4 of them, thank you. 2. Buffer Questions (Do 4 of 5 problems---6 pts each) a. Three different weak bases and their Kh values are listed below in a table. Which one would be best to form a buffer with a pH of 8.50? Explain why, and numerical calculations are expected as part of your answer to receive full credit. K = K,K) = 1.0 x 10-14 Weak Base K, Value KPK ammonia (1,8 x 10 hydrazine 1.3...
help with 5 and 6 please 5. Choose the effective pH range of a HF/Naf buffer. For HF, Ka = 3.5 x 10-4 6. If a small amount of a strong acid is added to buffer made up of a weak acid, HA, and the sodium salt of its conjugate base, NaA, the pH of the buffer solution does not change appreciably because a) the Ka of HA is changed. b) the strong acid reacts with Ato give HA, which...
please help!! calculate pH of solutions on second page a-c!! 1. (4 points) A buffer solution is created with C;H,NH, and 0.012 M C;HsNH2. The K, for C,H,NH2 is 4.7 х 104. What is the concentration of C,HNH, in the buffer solution that has a pH of 11.50? а. What is the concentration of the buffer solution if 0.0011 M HC is added to the buffer in part a.? b. Why is the buffer a basic solution? Could this weak...
help with these chemistry questions 1. Explain what happens to the concentration of H,O' ions in an acetic acid solution when solid sodium acetate is added. 2. Determine the pH and pH of a solution that is 0.5 M NaHSO4 and 0.25 M Na2SO4 3. When sodium nitrite is added to HNO2(aq) a) the equilibrium concentration of HCOOH(aq) decreases. b) the pH of the solution increases. c) the K increases. d) the pH of the solution does not change. e)...
how do you solve these? I am stuck. DUE AFTER COMPLETING LAB. ANSWER IN SPACE PROVIDED Determine the K, of the weak acid HX knowing that a 0.10 M solution of LiX has plH of 8.90. 1. Pyridine, C.H,N, is a weak base and reacts with HCI as folleows 2. C.H,N (aq)+ HCI (aq) CH,NH (aq) CI (aq) What is the pH of a 0.015 M solution of the pyridinium ion (CSH5NH+)? The K, for pyridine is 1.6 x 10-9....
5. (2pts) To calculate the pH of buffer solution we need to use Henderson-Hasselbalch equation The generic form of this equation is: 6. (8 points) What is the pH of a solution that contains 25 ml of 0.10 M HF and 25 ml 0.1M NaOH solution? (Ka of HF -6.8 x 104).
please explain how you got all your answers 10. Calculate the pH of a 0.30 M formic acid solution. (K-1.8 x 10") Weak monoprotic acid. 11. Calculate the K, for a 0.050 M solution of HA (weak acid) if the pH = 4.65. 12. What is the pH of the solution which results from mixing 50.0 mL of 0.30 M HF(aq) and 50.0 mL of 0.30 M NaOH(aq) at 25C? (K. of F = 1.4 x 10) 13. Which of...
21. Calculate the equilibrium concentration of the reactants and products if K·5.0 x 08 and initial, ulate the equilibrium concentration of the reactants and products if K 5.0 x 10and ini the [A] = 2.0 M (7 pts) C(g) B(g) + A(g) ←→ pts) 22. Use the following kinetic data to determine the rate law for the reaction. (7 Initial Rate (mol/L s 3.3 Experiment Initial [NO2l(M) Initial [O21(M 0.40 0.10 1.7 0.20 0.10 1.7 0.20 0.20 23. Calculate the...
17. The hydrogen sulfate or bisulfate ion HSO4 can act as either an acid or a base in water solution (a) Show the reaction where HSO4 acts an acid (Ka) (b) Show the reaction where HSO4 acts a base (Kb)? 18. Show the chemical equilibrium processes for Kal and Ka2 for diprotic H2SO3 and justify which Ka is the larger value 19. A buffer contains a weak acid, HA, that is twice the concentration of its conjugate base, A. If...
1. Rank the solutions in order of decreasing [H3O+]: 0.10 M HF, 0.10 M HCl, 0.10 M HClO, 0.10 M HC6H5O. 2. The beaker will be filled to the 0.50 L mark with a neutral solution. Set the pH to 3.95 by using the green arrows adjacent to the pH value indicated on the probe in the solution. Once you adjust the pH, note the corresponding OH− ion concentration in M as given in the graphic on the left side...