Question

Mileage Ratings for 2016 Hybrid Cars 50 25 31 32 42 31 31 28 29 41 29 28 42 28 37 50 26 45 41 30 21 40 56 34 47

1.Construct a frequency distribution for the hybrid cars with a class width of 2.

2.Explain why a class width of 2 is too narrow for these data.

3.Construct a relative frequency distribution for the hybrid cars with a class width of 3, where the first class has a lower limit of 20.

4.Construct a histogram based on this relative frequency distribution. Is the histogram unimodal or bimodal? Describe the skewness, if any, in these data.

5.Construct a frequency distribution for the non-hybrid cars with an appropriate class width.

6.Using this class width, construct a relative frequency distribution for the non-hybrid cars.

7.Construct a histogram based on this relative frequency distribution. Is the histogram unimodal or bimodal? Describe the skewness, if any, in these data.

8.Compare the histogram for the hybrid cars with the histogram for the non-hybrid cars. For which cars do the mileages vary more?

9. Construct a stem-and-leaf plot for each data set. Which do you think illustrates the comparison better, the histograms or the stem-and-leaf plot? Why?

Answer 1

Page not! 1) construct a frequency distribution for the hybrid cars with a class width of go . soll. Then, the frequency table for the hybrid card with a class width 2. Sales tervat Tally marks. Frequency M p 22-24 94-26 - O w 98 - 30 30-39 38-34 34-36 36-38 38-40 40-42 ho o Po 20 6 bola Re Re * 42 - 44 44-46 46-48 48.50 So-52 SS-84 84-56 56-58 -

Paje no!:2 2. Explain why a class width of a is too narrow for these data ? dot. In the above the class width of ma is not a good choice in any situation, because with this class width of 2 we get frequency of classes O", three times

3 construct a relative frequency distribution for the hybrid cars with a class wichth of 3, where the first class has a lower limit of zo. sol Relative frequency table with a class width of 3. slands interval frequency Relative frequency 556 -0.089 156 = 0.016 Relative frequency = frequery 20-23 23-26 956 016 26-29 29-30 32-35 10/56 199 3 456 3256 35-38 = 0.07 = 0.054 30-41 t 41-44 44-47 oon - 47 - 50 7/56 = 0.125 B/ S6 = D.143 3156 = 0.054 456 = 0.018 4756 - 0.071 0156 = 0 756 = 0.018 {fi = 56 50-53 53-56 56-59. o

page.no y, construct a histogram based on this relative frequen -cy distribution is the histogram unimodel cor) bimodal? Describe the skewness . if any, in these data. soll. The histogram is based on this relative frequ the below histogram is an multimodal. oozt .0016 t oolst Onlyt 0-13+ 0.08 Onthof Onost Do. ooost 02 1 20 23 86 89 32 35 38 41 un 47 so s 56 59 :