Question

An apparatus measures the probability density of an electron passing through it. The probability density data is shown in the graph below. Determine the probability of finding the electron in a narrow strip of width 0.008 nm centered at x, = 4.00 nm and x, = 7.00 nm. ) P(x)=\V (x ) ? (nm 0.500F 0.400 0.300 0.200 M. 0.1007 2.00 4.00 6.00 + x (nm) 8.00 probability at x1 0.0048 What is the probability density at xi? How is the probability of finding the electron in a narrow strip of width related to the probability density?

Answer 1

Answer: - Given that Width = 0.008 nm Xi 4 nm x2 = 7nm P(x) 2 14 (8) 1 2 (um') 0.008 PH) = 160 12 de - 1001? [x20003 19001 [0.008] 1011) [0.008 8x104 = 4. nm Plx) = at 0.0008 at x = 70m | 18x) 12 = 0 P(x) = 0 at x2 = 7inm