Question

Prove: An edge e of a graph G is a cut-edge if and only if e...

Prove:

An edge e of a graph G is a cut-edge if and only if e is not part of any circuit in G.

0 1
Add a comment Improve this question Transcribed image text
Answer #1

Proof: Consider that e=(x,y) is a cut edge , Suppose that there is a circuit of cycle (x, P, y, x) containing e. Then if Z = u, Z1, x, y, Z2, v is a walk from u to v using e, u, Z1, P, Z2, v is a walk from u to v that doesn’t use e. Thus e is not a cut edge .

If e is not a cut edge then G−e contains a path P from x to y (x ∼ y in G and relations are maintained after deletion of e). So (y, x, P, y) is a cycle containing e.

Add a comment
Know the answer?
Add Answer to:
Prove: An edge e of a graph G is a cut-edge if and only if e...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
Active Questions
ADVERTISEMENT