Question

part C, im not sure why my answer is wrong

At least one of the answers above is NOT correct. (1 point) Assume that Switzerland's population grows at a rate of 0.24 percent a year and that the 1988 population was 6.9 million. (a) Write an expression for the population as a function of time in years. (Let I = 0 in 1988.) P = 6.9E6*e^(.0024t) (b) How long will it take for the population to double from 1988 ? In(23/.0024 (c) If there is a net immigration of 10,000 people a year into Switzerland, write an expression for the population in year t. P= 6.9E6*e^(.0024t)+100001 In this case, how long will it take for the population to double from 1988 ? 217.39 Note: You can earn partial credit on this problem. Preview My Answers Submit Answers

Answer 1

Cc) Net immigration - 10000 per year Hence growth rate given by dp = 0.0024 P +10000 = db 0.0024[ P + 10.0..] rate variable & Integrate dp . ( 0 0 0 2 dt +10000 0.0024 - 0.00 24t the loP+ TOODD 0.0024 J 0.0024t - Ce Plt) + 10000 0.0024 0.00240 → Plt) = ce - 4166666-66 since PCO) = 6.9 million N 6. q xo . c ) - 4 6 6 6 6 6 6 4 → C - 11 6 6 6 6 6.66 0.00246 ... PCt. 11066666.66 e - 4166666.66 for doubling population 0.0024€ 13800000 = 11066666-661 4166666.66 0.0024 e 1.62349 t - In (1.62349) - 201.90 0-0024