Let Moment of inertia of the system when axis is passing through m1 be I1
I1= m2
32 + m3
52 = 6.1
9 + 7.9
25 = 252.4 kg m2
Let Moment of inertia of the system when axis is passing through m3 be I2
I2 = m1
52 + m2
42 = 9
25 + 6.1
16 = 322.6 kg m2
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Torque
about axis passing through m1 = r
F = 3
518 = 1554 N m
r and F are vectors and
r
F is cross product of vectors.
For torque
. Force vector is perpendicular to distance from point of
application to axis.
Torque
about axis passing through m3 = r
F = 0 , because force vector is parallel
to distance from point of application to axis.
---------------------------------------------------------------------------------
Angular acceleration
is obtained from ,
for the system-1, angular acceleration
= 1554/ 252.4 = 6.16 rad/s
angular velocity
after 5.99s =
t = 6.16*5.99 = 36.9 rad /s
for system-2,
= 0 , hence angular acceleration and angular velocity are zero
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