Question

TUU WISI U test the following claim (H) at a significance level of a = 0.05. H:H = 12 H:Hi # 2 You believe both populations are normally distributed, but you do not know the standard deviations for either. However, you also have no reason to believe the variances of the two populations are not equal. You obtain the following two samples of data. Sample #1 Sample #2 87. 165.4 72. 3 80. 2 65 73.5 71.9 78.1 83 71.5 92.1 85.1 65.1 77 57.1 | 82. 3 83.6 91.2 66.7 68 709 86. 9 72.8 74.8 77. 2 57.1 80.2 77.8 66.6 73.9 69.8 75.7 81.8 78.9 88. 7 94.7 71. 7 74.1 76.1 58.4 What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? For this calculation, use the degrees of freedom reported from the technology you are using. (Report answer accurate to four decimal places.) p-value = The p-value is. less than or equal to) a greater than a mietic leads to a decision to...

Answer 1

T = 12.0318 - 66.9956 22 09.9717 + 76.2783 18 - - 2.9532 P-valul : P-value = P(IT17 Tnto -2, 4) P(1-2-9532) 7 T22418-270025) = P(2.9532 7 T38,0.025) P-value = 0.005369 The P-value is less than a to a decision to... The o o o test reiect accept fail statistic leads the null the null. to relect the null Reject ie the null hypothesis 4, 7 ur is true & accept.

Page No. Date As such, the final conclusion is that o The the to Sample cluta support first population mean the second population the claim that I is not equal mean.

. Ans. Here we want to test Ho: Ha M,= ei la t llz at level of significance x = 0.05 we have given two Samples and assume that both the samples are from normal population Let x be Sample 1 & y be sumple2 . Here we don't know standard deviations for both the samples . Hence here we can use two Sample t-test under the assumption that, population variances are equal mean(x) 2 mean (y) = = y = 92.0318 79.9717 stard Standard error (x) = .E(Y) = 82 = E 8 = 8. 1850 8.7337 S = 66.9956 $2 = 16 2783 n = 22 Test Statistic h e n, - 18 18? + 53 Vana