If an object that is 7.50cm tall is viewed through a lens with a magnification of 3.00, what is the height of the image?
A. 2.25cm
B. 7.50cm
C. 8.22cm
D. 22.5cm
If an object that is 7.50cm tall is viewed through a lens with a magnification of...
A 20 cm tall object is located 70 cm away from a diverging lens
that has a focal length of 20 cm. Use a scaled ray tracing to
answer parts a-d.
a. Is the image real or virtual?
b. Is the image upright or inverted?
c. How far from the lens is the image?
d. What is the height of the image?
e. Now use the thin lens equation to calculate the image
distance and the magnification equation to determine...
A 6.2 ?? tall object is placed 14.3 ?? in front of a −4.5 ? lens. uns a. What type of lens is this? b. Where is the image located? c. Is this a real or virtual image? d. What is the magnification of the image? e. Is the image upright or inverted?
A 4.0 cm tall object is 5.0 cm in front of a diverging lens with a focal length of -6.0 cm. A converging lens with a focal length of 6.0 cm is located 8.0 cm behind the diverging lens. (As viewed from the side, from left to right, the sequence is object - diverging lens - converging lens - observer. Rays then travel from left to right through the system.) (a) Use ray tracing to draw image 1 and image...
A converging lens with a focal length of 12.0cm forms a virtual image 8.00mm tall. Image is 17.0cm from the lens. Calculate (a)the position of the object, (b)magnification of the lens, (c)height of the object. (d)Is the image upright or inverted? (e) Are the object and image on the same side or opposite sides of the lens? (f) Draw ray-diagram
A 4.0 cm tall object is placed 8 cm in front of a double-convex lens (n = 1.52). The height of the image is y'- 7.0 cm. Based on this information find: a) The magnification, m. b) The image distance, s'. c) The focal length of this lens, f.
A 4.0 cm tall object is placed 8 cm in front of a double-convex lens (n = 1.52). The height of the image is y’ = 7.0 cm. Based on this information find: a) The magnification, m. b) The image distance, s'. c) The focal length of this lens, f.
A 4.0 cm tall object is placed 8 cm in front of a double-convex lens (n = 1.52). The height of the image is y' = 7.0 cm. Based on this information find: a) The magnification, m. b) The image distance, s'. c) The focal length of this lens, f.
A 4.0 cm tall object is placed 50.0 cm from a diverging lens having a focal length of magnitude 20.0cm. a. What is the location of the image? b. What is the magnification of the image? c. Is the image inverted or upright? d. Is the image virtual or real?
A 5 cm tall object is 20 cm in front of a diverging lens with a focal length of 10 cm. a) What is the location of the image? cm b) What is the height of the image? cm c) The image is:real or virtual d) The image is: inverted or upright
A 4.0-cm tall object is placed 50.0 cm from a diverging lens having a focal length of magnitude 25.0 cm. Draw the ray diagram for this situation. What is the location and height of the image? Is the image real or virtual? • Draw an optical axis with the lens centered on the axis. Represent the object at the correct distance from the lens • Draw the three "special rays" from the top of the object • Extend the rays...