An equal tangent vertical curve of length 420 ft connects a +2.25 % initial grade and a -2.75 % final grade. What is the design speed of the curve?
An equal tangent vertical curve of length 420 ft connects a +2.25 % initial grade and...
An equal-tangent vertical curve connects an initial grade of +2% and-2%. The PVI is located at an elevation of 1000 feet. If the design speed is 60 mi/h and the curve is designed for stopping sight distance, then what is the elevation of the PVT, in feet?
A 500-ft-long equal-tangent crest vertical curve connects tangents that intersect at station 340 + 00 and elevation 1322 ft. The initial grade is +4.0% and the final grade is -2.5%. Determine the elevation and stationing of the high point, PVC, and PVT. Solve this problem using parabolic equation and offset method.
7. A sag vertical curve connects a-4.75% grade and a +3.75% grade. The PVI is at station 45+90.00 at an elevation of 611.00 ft. The design speed is 50 mi/h. Determine the minimum length of the vertical curve using the AASHTO method ("K" factors). Round the minimum length up to the next 10 ft multiple for design of the vertical curve and associated calculations. Using this length, determine: The station and elevation of the PVC The station and elevation of...
25. A spiral curve with a length of 50 feet connects a tangent to a curve having a radius of 100 feet. Deter- mine the offset from the tangent to the point where the spiral connects to the curve and the length of throw from the tangent. 26. Given a spiral curve with a length of 150 feet, which connects a tangent to a curve having a radius of 200 feet, determine the offsets from the tangent to the midpoint...
3. A 300 ft vertical curve connects a-2.3% approach grade and a +1.6% departure grade. The PVI is at 45+65 with elevation 369.22'. The curve is designed for 35 mi/hr speed limit. Calculate stations and elevations for PVC and PVT A 4% grade meets a failing grade of-25%. Station at P1 is at 60+00 and elevation is 95 feet. The length between PVC and PVT is 1400 feet. Find the elevation of the curve at station 58+00 4. 3. A...
An equal-tangent crest vertical curve has a 50-mi/h design speed. The initial grade is +3%. The high point is at station 33 + 40.76 and the PVT is at station 37 + 24.66. What is the elevation difference between the high point and the PVT?
A crest vertical curve connects a +2% grade and a -2.05% grade. The PVI is at station 40+00.00 at an elevation of 100.00 ft. The design speed is 70 mi/h. If the length is 1084 ft, determine: (b) The station of the BVC (3 pts (c) The elevation of the BVC (3 pts (d) The station of the EVC (3 pts) (e) The elevation of the EVC (3 pts) (1) The station of the highest point on the curve (4...
2. A crest vertical curve is to be designed by joining a +4% initial tangent with a final -3% tangent. The station location and elevation of VPC are 250+45 and 500 ft respectively. The design speed is 50 mph on the curve. Using AASHTO geometric design guideline, determine: (a) Station location of VPT. (b) Vertical offset at each 1/4 of length distance from VPC.
(10 pts) A crest curve with an initial tangent grade of 3.7% and a final tangent grade of-4.1% has a length of 1400 feet. What is the maximum recommended speed limit for the curve?
13. A 400-ft long equal tangent sag vertical curve has its PVC at station 100+00 and o b elevation 500 ft, the initial grade g,--4% and the final grade g2 elevation of the lowest point of the curve. +2.5%. Determine the