Question

QUESTION 4 3 pc For the circuit in the figure, Em1 8m2 = 8m5 = 773 MAX. m3 - m4 = 592 PA/V, T01 = '02-'05 - 416 ko. To3=104 = 218 ko. what is the common-mode rejection ratio in VN? (0 decimal places, within 100) MTH M

Answer 1

ANSWER

Given that

common mode rejection ratio (CMRR) : It is a differential amplifier (or other device) is a metric used to quantify the ability of the device to reject common-mode signals, i.e. those that appear simultaneously and in-phase on both inputs. An ideal differential amplifier would have infinite CMRR, however this is not achievable in practice. A high CMRR is required when a differential signal must be amplified in the presence of a possibly large common-mode input, such as strong electromagnetic interference (EMI).

given circuit: Ma o Vans H M VI gom, a 9m2 agost 2773 MA/v. qm Bagmu2 892 41 A/N. No1 2002:2005 sulokk No 3. =8042218KR CMRR ? | Adl 9miz (rovie || r03,4).9ms.y CI 77891, 2, 405) 9m 1,2. (1+29mi, 2 805) 9m3,4 (ro,, 211803,4).

.(i+2(7731). 416k) 592 M (416K (1 218k) 2 R sasa 098c. 3 1.546 x 1126 173.152 il CMRR2 Ans.