Question

1. How many moles of NaCl (s) can be formed from 32 moles of Cl2 (g) reacting with an excess of Na (s)? Na (s) + Cl2 (g) -> NaCl (s) 2. How many moles of H2CO, can be formed from 2 moles of HCl reacting with an excess of Na2CO3? HCI + Na2CO3 -> NaCl + H2CO3

Answer 1

1)balanced chemical equation for the formation of NaCl will be Na + 0.5Cl2 ----> NaCl

Since Na is in excess, formation of NaCl will depend upon Cl2

Acc to above equation 0.5 mole of Cl2 gives 1 mole of NaCl

So 32 moles of Cl2 will give (1/0.5)*32 moles of NaCL (unitary method)

Hence we will have 64 moles of NaCl

2) Balanced chemical equation will be 2HCl + Na2CO3 ---> 2NaCl + H2CO3

Since Na2CO3 is in excess, the formation of product will depend upon HCl

hence 2 moles of HCl will form 1 mole of H2CO3